3x^2=10x+30

Solution for 3x^2=10x+30 equation:

3x^2=10x+30

We move all terms to the left:

3x^2-(10x+30)=0

We get rid of parentheses

3x^2-10x-30=0

a = 3; b = -10; c = -30;
Δ = b2-4ac
Δ = -102-4·3·(-30)
Δ = 460
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{460}=\sqrt{4*115}=\sqrt{4}*\sqrt{115}=2\sqrt{115}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2\sqrt{115}}{2*3}=\frac{10-2\sqrt{115}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2\sqrt{115}}{2*3}=\frac{10+2\sqrt{115}}{6}
$